14k^2-32k+8=0

Solution for 14k^2-32k+8=0 equation:

14k^2-32k+8=0

a = 14; b = -32; c = +8;
Δ = b2-4ac
Δ = -322-4·14·8
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-24}{2*14}=\frac{8}{28}
=2/7
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+24}{2*14}=\frac{56}{28}
=2
$